Question

What are the zeros of the quadratic function f(x)=6x^2+12x-7

Answer 1

Answer:

Use the quadratic formula

[-12 +/- square root (12^2- (4)(6)(-7))]/2(6)

[-12 +/- square root (312)]/12

-1+(1/6) square root (78)

and 

-1-(1/6) square root (78)