Respuesta :
Answer:
Option C.
Step-by-step explanation:
The given equation is
[tex]\log \dfrac{x}{2}+\log \dfrac{20}{x^2}=\log 8[/tex]
Using properties of logarithm, we get
[tex]\log \left (\dfrac{x}{2}\times \dfrac{20}{x^2}\right)=\log 8[/tex] [tex][\because \log A+\log B=\log AB][/tex]
[tex]\log \left (\dfrac{10}{x}\right)=\log 8[/tex]
On comparing both sides, we get
[tex]\dfrac{10}{x}= 8[/tex]
[tex]\dfrac{10}{8}=x[/tex]
[tex]\dfrac{5}{4}=x[/tex]
[tex]x=\dfrac{5}{4}[/tex]
Therefore, the correct option is C.
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