Can someone plz explain this to me i would appreciate the help!

Answer: [tex]\frac{6}{65}[/tex]
Step-by-step explanation:
[tex]\frac{\frac{1}{2}-\frac{2}{5} }{\frac{1}{3}+\frac{3}{4}}[/tex]
Let's solve each separately.
[tex]\frac{1}{2}-\frac{2}{5}=\frac{(1)(5)-(2)(2)}{(2)(5)} =\frac{5-4}{10} =\frac{1}{10}[/tex]
[tex]\frac{1}{3}+\frac{3}{4}=\frac{(1)(4)+(3)(3)}{(3)(4)} =\frac{4+9}{12} =\frac{13}{12}[/tex]
This leaves the fraction as;
[tex]\frac{\frac{1}{10} }{\frac{13}{12} }[/tex]
To get rid of the fraction in the denominator, multiply by its reciprocal. The reciprocal of a fraction is the same fraction but inverted.
[tex]\frac{\frac{1}{10} }{\frac{13}{12} }*\frac{12}{13}[/tex]
This will eliminate the denominator, leaving the fraction like;
[tex]\frac{1}{10}*\frac{12}{13}[/tex]
12 and 10 can be simplified.
12/2=6
10/2=5
Our new fraction would be;
[tex]\frac{1}{5}*\frac{6}{13}[/tex]
Multiply;
[tex]\frac{6}{65}[/tex]