Respuesta :

Answer: [tex]\frac{6}{65}[/tex]

Step-by-step explanation:

[tex]\frac{\frac{1}{2}-\frac{2}{5} }{\frac{1}{3}+\frac{3}{4}}[/tex]

Let's solve each separately.

[tex]\frac{1}{2}-\frac{2}{5}=\frac{(1)(5)-(2)(2)}{(2)(5)} =\frac{5-4}{10} =\frac{1}{10}[/tex]

[tex]\frac{1}{3}+\frac{3}{4}=\frac{(1)(4)+(3)(3)}{(3)(4)} =\frac{4+9}{12} =\frac{13}{12}[/tex]

This leaves the fraction as;

[tex]\frac{\frac{1}{10} }{\frac{13}{12} }[/tex]

To get rid of the fraction in the denominator, multiply by its reciprocal. The reciprocal of a fraction is the same fraction but inverted.

[tex]\frac{\frac{1}{10} }{\frac{13}{12} }*\frac{12}{13}[/tex]

This will eliminate the denominator, leaving the fraction like;

[tex]\frac{1}{10}*\frac{12}{13}[/tex]

12 and 10 can be simplified.

12/2=6

10/2=5

Our new fraction would be;

[tex]\frac{1}{5}*\frac{6}{13}[/tex]

Multiply;

[tex]\frac{6}{65}[/tex]

RELAXING NOICE
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