Question

a bag contains 6 white marbles and 4 black marbles. a marble is drawn without replacing the first one. what is the probability of drawing a white marble on the first draw, followed by a white marble on the second?

Answer 1

Answer:

6  = white marbles

4  = black marbles

10 =  total marbles

6/10 - Pulling white marbles

4/10 - Pulling black marbles

10 - 4 = 6

2/6 - Pulling two white marbles

2/6 = 1/3 = 0.33 or 33%

I hope this helped!

Answer 2

The probability of drawing a white marble on the first draw after following the second draw of white marble should be 0.33.

Given that

• There are 6 white marbles.
• There are 4 black marbles.
• The total marbles are 10.

Now based on the above information

Put white marbles be $\frac{6}{10}$

And, black marbles be $\frac{4}{10}$

So,

= 10 - 4

= 6

Now pull two white marbles i.e.

$= \frac{2}{6} \\\\= \frac{1}{3}\\\\= 33\%\ or\ 0.33$

Therefore we can conclude that The probability of drawing a white marble on the first draw after following the second draw of white marble should be 0.33.

Learn more about the probability here: brainly.com/question/11234923