Question

you have five $1 bills, four $5 bills, six $10 bills, and three $20 bills you select a bill at random, without replacing the bill what is the probability of a 1 then a ten?
a.11/35
b.5/51
c.5/54
d.193/306

Answer 1

Answer:

Option B.

Step-by-step explanation:

It is given that,

Number of $1 bills = 5

Number of $5 bills = 4

Number of $10 bills = 6

Number of $20 bills = 3

So,

Total number of bills = 5 + 4 + 6 + 3 = 18

We need to find the probability of a 1 then a ten (without replacement).

Probability of selecting $1 bill in first draw $=\dfrac{5}{18}$

After one draw, the number of remaining bills is 18 - 1 = 17.

Probability of selecting $10 bill in second draw $=\dfrac{6}{17}$

The probability of a 1 then a ten is

$P=\dfrac{5}{18}\times \dfrac{6}{17}=\dfrac{5}{51}$

Therefore, the correct option is B.