Answer:
6‑phosphate ⟶ fructose 6‑phosphate fructose 1,6‑bisphosphate ⟶ glyceraldehyde 3‑phosphate.
Explanation:
Glucose is a high energy rich stable compound, which does not react easily.Therefore inorder to extract the energy in its glycosidic bonds, so that subsequent reaction in the glycolytic pathways can be easier. One molecule of glucose must be phosphorylated by 2 molecules of ATPs..
The first step involves the formation of glucose phosphate(6-phosphate), which is converted to fructose 6 phosphate by hydrolysis of 1 ATP molecule.
The later is later converted , in presence of hydrolysis of the second ATP to form fructose 1, 6 bisphosphate. These two steps are called phosphorylation.
The latter is converted to 2 molecules of 3C compounds called glyceraldehyde -3-phosphate or triose phosphate.
From the point onward the reaction steps are faster to produce ATPs and Pyruvate. 4ATPs are formed, but the 2ATPs used above are deducted. so net 2ATPs formed.
