Question

the number of moles of O2 in 2.24 L of O2 gas.

calculate at STP

Answer 1

Answer:

0.1 mol O2

Explanation:

1 mol of any gas at STP = 22.4 L

2.24L/22.4L = 0.1

1mol * 0.1 = 0.1 mol

you have 0.1 mol of O2

Answer 2

The number of moles of $O_2$  is required.

The number of moles of $O_2$ is 0.2 moles.

V = Volume = 2.24 L

$\rho$ = Density of $O_2$ at STP = 1.429 g/L

M = Molar mass of $O_2$ = 16 g/mol

Density is given by

$\rho=\dfrac{m}{V}\\\Rightarrow m=\rho V\\\Rightarrow m=1.429\times 2.24\\\Rightarrow m=3.20096\ \text{g}$

Molar mass is given by

$M=\dfrac{m}{n}\\\Rightarrow n=\dfrac{m}{M}\\\Rightarrow n=\dfrac{3.20096}{16}\\\Rightarrow n=0.2\ \text{moles}$

The number of moles of $O_2$ is 0.2 moles.

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