The energy required to move a 4.00-micro coulomb charge through a potential difference of 36.0 volts will be 1.44 X 10⁻⁴ J.
The amount of work performed in an electrical field to move a unit charge from one location to another is defined as the electrical potential difference.
The given data in the problem is;
W is the energy =?
q is the charge = 4.00-microcoulomb
V is the potential difference = 36.0 volts
The electric potential is the ratio of electric potential energy and charge.
[tex]\rm V= \frac{W}{q} \\\\\ W=Vq \\\\ W= 36.0 \times 4.00 \times 10^{-6} \\\\ W=144 \times 10^{-6} \\\\ W=1.44 \times 10^{-4}[/tex]
Hence the energy required will be 1.44 × 10⁻⁴ J.
To learn more about the electric potential difference refer to the link;
https://brainly.com/question/9383604
