Answer:
a) 10.34% probability that, in a year, there will be 4 hurricanes.
b) 3.62 years are expected to have 4 hurricanes
c) Either 3 or 4 hurricanes(discrete number) are close to the mean of 3.62, which means that the Poisson distribution works well in this case.
Step-by-step explanation:
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:
[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]
In which
x is the number of sucesses
e = 2.71828 is the Euler number
[tex]\mu[/tex] is the mean in the given interval.
6.7 per year.
This means that [tex]\mu = 6.7[/tex]
a. Find the probability that, in a year, there will be 4 hurricanes.
This is P(X = 4).
[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]
[tex]P(X = 4) = \frac{e^{-6.7}*(6.7)^{4}}{(4)!} = 0.1034[/tex]
10.34% probability that, in a year, there will be 4 hurricanes.
b. In a 35-year period, how many years are expected to have 4 hurricanes?
Each year, 0.1034 probability of 10 hurricanes.
In 35 years
35*0.1034 = 3.62
3.62 years are expected to have 4 hurricanes
c. How does the result from part (b) compare to a recent period of 35 years in which 3 years had 4 hurricanes? Does the Poisson distribution work well here?
Either 3 or 4 hurricanes(discrete number) are close to the mean of 3.62, which means that the Poisson distribution works well in this case.