Question

given that f(1)=2 and f'(1)=4, find the derivative of f(x)loge(x) when x=1

Answer 1

Answer:

2

Step-by-step explanation:

loge(x) is ln(x)

f(x) × ln(x)

Differentiate using product law

[ln(x) × f'(x)] + [(1/x) × f(x)]

x = 1

[ln(1) × f'(1)] + [(1/1) × f(1)]

(0 × 4) + (1 × 2)

0 + 2

2