Respuesta :
Answer:
P(Y and R) = P(Y)*P(R) + P(R)*P(Y)
P(Y and R) = 16/125 = 0.128 = 12.8%
Step-by-step explanation:
There are 8 Yellow marbles in the bag
There are 9 Green marbles in the bag
There are 3 Purple marbles in the bag
There are 5 Red marbles in the bag
The total number of marbles in the bag are
Total marbles = 8 + 9 + 3 + 5 = 25
We want to find the probability of selecting two marbles that is one Yellow marble and one Red marble from the bag.
The probability of selecting a Yellow marble is given by
P(Y) = number of Yellow marbles/total number of marbles
P(Y) = 8/25
The probability of selecting a Red marble is given by
P(Y) = number of Red marbles/total number of marbles
P(Y) = 5/25
P(Y) = 1/5
It is possible that the first marble selected is Yellow and the second is Red, and it is also possible that first marble selected is Red and the second is Yellow.
P(Y and R) = P(Y)*P(R) + P(R)*P(Y)
P(Y and R) = (8/25)*(1/5) + (1/5)*(8/25)
P(Y and R) = 16/125
P(Y and R) = 0.128
P(Y and R) = 12.8%
Answer:
probability of selecting one yellow and one red = 2/15
Step-by-step explanation:
We are told there are;
8 yellow marbles
9 green marbles
3 purple Marbles
5 red Marbles
Since two Marbles are selected,
Number of ways of selecting one yellow and one red is:
C(8,1) x C(5,1) = 8!/(1!(8 - 1)!) x 5!/(1!(5 - 1)!)
This gives 40
Now, the total number of Marbles in the question will be;
8 + 9 + 3 + 5 = 25 Marbles
Thus, number of ways to select any two Marbles from the total is;
C(25,2) = 25!/(2!(25 - 2)!) = 300
Thus; probability of selecting one yellow and one red = 40/300 = 2/15