Question

A 1.5kg mass attached to an ideal spring oscillates horizontally with an amplitude of 0.50m. The spring constant is 85 n/m. what is the frequency of the mass's motion?

Answer 1

Answer:

frequency of the mass motion $f$ ≅ 1.2 Hz

Explanation:

Given that:

Mass m = 1.5 kg

Amplitude A = 0.50 m

Spring constant k = 85 n/m

The frequency can be calculated by using the formula:

$f = \frac{1}{2 \pi} \sqrt{\frac{k}{m} }$

$f = \frac{1}{2 \pi} \sqrt{\frac{85}{1.5} }$

$f = 1.198$ Hz

frequency of the mass motion $f$ ≅ 1.2 Hz

Answer 2

The frequency of the mass's motion is equal to 1.20 Hertz

Given the following data:

• Mass = 1.5 kilograms

• Amplitude = 0.5 meter

• Spring constant = 85 N/m

To determine the frequency of the mass's motion:

Mathematically, the frequency of an object in simple harmonic motion (SHM) is given by the formula:

$F = \frac{1}{2\pi} \sqrt{\frac{k}{m} }$

Where:

• k is the spring constant.

• m is the mass of an object.

Substituting the given parameters into the formula, we have;

$F = \frac{1}{2\pi} \sqrt{\frac{85}{1.5} }\\\\F=\frac{1}{6.284} \times \sqrt{56.67} \\\\F = 0.1591 \times 7.5280$

Frequency = 1.20 Hertz

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