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Wolfyy

We need to find the hypotenuse of the triangle. We can find that by using the Pythagorean theorem: a² + b² = c²

Solve with the given values of the triangle:

2² + 4² = c²

4 + 16 = c²

20 = c²

√20 = √c²

4.47 ≈ c

Find the area of the square using: A = bh

4.47 * 4.47 = 19.9809

Therefore, the area of the square is approximately 19.9809units²

Best of Luck!

Answer:

Step-by-step explanation:

We've got clues. First of all, we have a right triangle with measure of both legs. We can use the Pythagorean theorem to find the third side. Then, we have a square that shares the third side. This means that the square's side will be as long as the hypotenuse of the triangle, which will give us the area of the square.

First use the Pythagorean theorem to find the hypotenuse:

[tex]a^2+b^2=c^2[/tex]

a and b are the legs and c is the hypotenuse. The hypotenuse is the side opposite the 90° (or the little square in the corner) and will always be the longest side in a right triangle.

Insert values:

[tex]4^2+2^2=c^2[/tex]

Simplify exponents:

[tex]16+4=c^2\\20=c^2[/tex]

Find the square root of both sides:

[tex]\sqrt{20} =\sqrt{c^2} \\\\4.5=c[/tex]

C is approximately 4.5 units (or [tex]2\sqrt{5}[/tex] )

To find the area, use the formula [tex]A=l*w[/tex]. Since this is a square, all sides are the same:

[tex]A=4.5*4.5\\A=20.25[/tex]

The area of the square is approximately 20.3 units.

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