Question

A 32 g sample of LiCl is dissolved in water to for 655 mL of solution. What is the molarity of the solution?
1.1 x 10-3 M LICI
1.1 M LICI
4.9 x 10-2 M LICI
49 M LICI

Answer 1

Answer : The molarity of the solution is, 1.1 M LiCl

Explanation : Given,

Mass of $LiCl$ = 32 g

Volume of solution = 655 mL

Molar mass of $LiCl$ = 42.4 g/mole

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

$\text{Molarity}=\frac{\text{Mass of }LiCl\times 1000}{\text{Molar mass of }LiCl\times \text{Volume of solution (in mL)}}$

Now put all the given values in this formula, we get:

$\text{Molarity}=\frac{32g\times 1000}{42.4g/mole\times 655mL}=1.1mole/L=1.1M$

Therefore, the molarity of the solution is, 1.1 M LiCl