Answer:
91.64L
Explanation:
Step 1:
Data obtained from the question.
This includes the following:
Initial volume (V1) = 43L
Initial pressure (P1) = 1.3 atm
Final volume (V2) =..?
Final pressure (P2) = 0.61 atm
Step 2:
Determination of the final volume.
To solve for the final volume, we'll apply the Boyle's law equation since the temperature is constant. The final volume is obtained as follow:
P1V1 = P2V2
1.3 x 43 = 0.61 x V2
Divide both side by 0.61
V2 = (1.3 x 43)/0.61
V2 = 91.64L
Therefore, the new volume is 91.64L
The volume will be 91.64 L when the pressure is 0.61 atm
From Boyle's law equation, we have that
P₁V₁ = P₂V₂
Where P₁ is the initial pressure
V₁ is the initial volume
P₂ is the final pressure
and V₂ is the final volume
From the given information
P₁ = 1.3 atm
V₁ = 43 L
P₂ = 0.61 atm
V₂ = ?
Putting the parameters into the formula, we get
1.3 × 43 = 0.61 × V₂
∴ [tex]V_{2} = \frac{1.3 \times 43}{0.61}[/tex]
V₂ = 91.64 L
Hence, when the pressure is 0.61 atm, the volume will be 91.64 L
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