Answer:
39secs
Step-by-step explanation:
Using the equation of motion
S = ut + 1/2gt²
S is the distance or height covered by the golf ball.
t is the time taken by the ball to hit the ground
U us the initial speed of the ball
g is the acceleration due to gravity.
g will be negative since the body acts against gravity
Given S = 0feet
u = 192ft/s
g = -9.81m/s²
t = ?
Substituting the parameters into the formula:
0 = 192t-1/2(9.81)t²
-192t = -4.91t²
4.91t = 192
t = 192/4.91
t = 39.1secs
The time taken by the golf ball to hit the ground is approximately 39secs
Answer:
option C.
Step-by-step explanation:
Given,
Initial speed of the ball, v = 192 ft/s
Distance travel, h(t) = 0 ft
Acceleration due to gravity, g = 32 ft/s²
Using equation of motion
[tex]s = ut + \frac{1}{2}gt^2[/tex]
[tex]0 = 192t - \frac{1}{2}\times 32t^2[/tex]
[tex]16t(t-12)=0[/tex]
t = 12 s.
Hence, the time for which ball was in the air is equal to 12 s.
Hence, the correct answer is option C.
