Answer:
V1P1=V2P2
155(22L)=P(10L0
P=341kPg
Explanation:
The following format is copied directly from your notes for how to solve these!!!
1) Analyze problem statement to find knowns and unknowns for each gas variable
V1 = 22.0 L P1 = 155.0 kPa T1 = T2 n = constant (same sample of gas)
V2= 10.0 L P2 = ? kPa T2 = T1 temperature is constant
2) Decide which of the gas laws to use and write its formula.
Only P and V are given, so Boyle's law is used P1V1 = P2V2
3) Change any temperature values to Kelvin (if T is needed) not needed
4) Plug in the knowns - INCLUDING UNITS!!
P1V1 = P2V2
(155.0 kPa) (22.0 L) = P2 (10.0 L)
P2 = (155.0 kPa)(22.0 L) = 341 kPa
(10.0 L)The following format is copied directly from your notes for how to solve these!!!
1) Analyze problem statement to find knowns and unknowns for each gas variable
V1 = 22.0 L P1 = 155.0 kPa T1 = T2 n = constant (same sample of gas)
V2= 10.0 L P2 = ? kPa T2 = T1 temperature is constant
2) Decide which of the gas laws to use and write its formula.
Only P and V are given, so Boyle's law is used P1V1 = P2V2
3) Change any temperature values to Kelvin (if T is needed) not needed
4) Plug in the knowns - INCLUDING UNITS!!
P1V1 = P2V2
(155.0 kPa) (22.0 L) = P2 (10.0 L)
P2 = (155.0 kPa)(22.0 L) = 341 kPa
(10.0 L)
