Respuesta :

Answer:

[tex]a_{n} = 32(\frac{1}{4})^{n-1}[/tex]

Step-by-step explanation:

The nth term of a geometric sequence is given by the following equation.

[tex]a_{n+1} = ra_{n}[/tex]

In which r is the common ratio.

This can be expanded for the nth term in the following way:

[tex]a_{n} = a_{1}r^{n-1}[/tex]

In which [tex]a_{1}[/tex] is the first term.

This means that for example:

[tex]a_{3} = a_{1}r^{3-1}[/tex]

So

[tex]a_{3} = a_{1}r^{2}[/tex]

[tex]2 = a_{1}(\frac{1}{4})^{2}[/tex]

[tex]2 = \frac{a_{1}}{16}[/tex]

[tex]a_{1} = 32[/tex]

Then

[tex]a_{n} = 32(\frac{1}{4})^{n-1}[/tex]

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