Answer:
[tex]a_{n} = 32(\frac{1}{4})^{n-1}[/tex]
Step-by-step explanation:
The nth term of a geometric sequence is given by the following equation.
[tex]a_{n+1} = ra_{n}[/tex]
In which r is the common ratio.
This can be expanded for the nth term in the following way:
[tex]a_{n} = a_{1}r^{n-1}[/tex]
In which [tex]a_{1}[/tex] is the first term.
This means that for example:
[tex]a_{3} = a_{1}r^{3-1}[/tex]
So
[tex]a_{3} = a_{1}r^{2}[/tex]
[tex]2 = a_{1}(\frac{1}{4})^{2}[/tex]
[tex]2 = \frac{a_{1}}{16}[/tex]
[tex]a_{1} = 32[/tex]
Then
[tex]a_{n} = 32(\frac{1}{4})^{n-1}[/tex]