Question

The width of a rectangle is doubled and its length is tripled.
How many times larger is the area of the enlarged rectangle compared to the area of the original rectangle?

a. 6
B. 10
C. 12
d. 24

Answer 1

Answer:

i think it is 12

Step-by-step explanation:

Answer 2

6 times larger is the area of the enlarged rectangle compared to the area of the original rectangle.

What is a rectangle?

"A Rectangle is a four sided-polygon, having all the internal angles equal to 90 degrees. The two sides at each corner or vertex, meet at right angles."

What is area of rectangle?

"The area of the rectangle is the region enclosed by the perimeter of the rectangle and is equal to product of length and width."

Let $l$ be the length and $b$ be the width of the original rectangle.

Let $l^{'}$ be the length and $b^{'}$ be the width of the enlarged rectangle.

Formula for area of rectangle

A = length × width

Area of original rectangle

A = $l$×$b$

Area of enlarged rectangle

$A^{'}$$= l^{'}$ × $b^{'}$

$A^{'}$$=3l$×$2b$

$A^{'}$$=6lb$

Hence, 6 times larger is the area of the enlarged rectangle compared to the area of the original rectangle.

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