dianamarie1 dianamarie1

29-04-2020
Chemistry

contestada

How many atoms are present in 179.0 g of iridium?
include units please:)!

Respuesta :

s138359 s138359

29-04-2020

Answer:

179.0 g of iridium (1 mol / 192.217 g) ( 6.022 x 10^23 atoms / 1 mol ) = 5.61 x 10^23 atoms of iridium

Explanation:

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cama0366 cama0366

29-04-2020

Answer:

A. 5.606x10²³atoms

Explanation:

Answer Link

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