Question

In the function f(x)=(x-2)^2+4, the minimum value occurs when x is
A.)-2
B.)2
C.)-4
D.)4.

Answer 1

Answer:

B

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

f(x) = (x - 2)² + k ← is in vertex form

with (h, k) = (2, 4)

Thus the minimum value is 4 when x = 2 → B

Answer 2

The value of the x should be 2.

Calculation of the value of x:

Since the function is $f(x)=(x-2)^2+4$

Here,

The equation of a parabola should be in vertex form i.e.

$y = a(x - h)^2 + k$

Hee (h, k) are the coordinates of the vertex and a should be the multiplier

So here h and k be 2 and 4

So here the minimum value should be 2

Therefore, The value of the x should be 2.

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