Question

What is the molarity of a 50.0 mL solution that contains 0.0350 mol of sodium sulfate, Na2SO4?
0.007 mol/L
0.07 mol/L
0.0007 mol/L
0.7 mol/l

Answer 1

Answer:

The molarity of a 50.0 mL solution that contains 0.0350 mol of sodium sulfate 0.7 $\frac{moles}{liter}$

Explanation:

Molarity is a concentration measure that indicates the amount of moles of solute that appear dissolved in each liter of the mixture.

So, the Molarity of a solution is determined by the expression:

$Molarity (M)=\frac{number of moles of solute}{volume}$

Molarity is expressed in units ($\frac{moles}{liter}$).

In this case:

• number of moles= 0.0350

• Volume=50 mL=0.05 L (1 L= 1,000 mL)

Replacing:

$Molarity=\frac{0.0350 moles}{0.05 L}$

Molarity= 0.7 $\frac{moles}{liter}$

The molarity of a 50.0 mL solution that contains 0.0350 mol of sodium sulfate 0.7 $\frac{moles}{liter}$