Question

Aqueous silver nitrate (AgNO₃) and aqueous sodium bromide (NaBr) react to produce solid silver bromide (AgBr) and aqueous sodium nitrate (NaNO₃). The reaction that occurs is as follows: $AgNO3(aq) + NaBr(aq) \rightarrow AgBr(s) + NaNO3(aq)$If the reaction was carried out, what would the mass of the precipitate tell you _________.

Answer 1

Answer:

Amount of bromide ion present

Explanation:

The reaction of aqueous silver nitrate with sodium bromide could be a method of gravimetrically determining the concentration of the bromide ion present. It has been an old analytical technique in chemistry to determine the concentration of an ion by precipitating the ion using the appropriate precipitating agent and weighing the precipitate.

By determining the mass of the bromide ion reacted we could also discover the amount of sodium bromide that originally reacted.

Answer 2

Answer:

The mass of the precipitate will give the amount/concentration of Bromide ion present in the reaction setup, thereby indirectly giving the amount/concentration of NaBr (aq) that we started with.

Explanation:

$AgNO3(aq) + NaBr(aq) \rightarrow AgBr(s) + NaNO3(aq)$

From the mass of AgBr precipitate formed, we can obtain the mass of Br originally in the NaBr sample we started with, using the percentage by mass of Br in the AgBr precipitate multiplied by the mass of precipitate obtained.

This answer can then be used in a similar method to obtain the mass of NaBr we started with.

Mass of Br in AgBr = (Mass of precipitate obtained) × [(molar mass of Br)/(molar mass of AgBr)]

Mass of NaBr we started with = (Mass of Br in precipitate) × [(Molar Mass of NaBr)/(Molar mass of Br)]

The mass of the precipitate will give the amount/concentration of Bromide ion present in the reaction setup, thereby indirectly giving the amount/concentration of NaBr (aq) that we started with.

Hope this Helps!!!