Explanation:
Solution 86P
Here, we have to determine the amount of sodium hydroxide required to precipitate all of the Mg.
Mg2+(aq) +2 NaOH(aq) ------> Mg(OH)2 (s) + 2Na+(aq)
Therefore
Molar mass of NaOH =39.997 g/mol
Molar mass of Mg =24.305 g/mol
Thus,the conversion factors
g NaOH(aq)= mol NaOH(aq) = g Mg = mol Mg
Thus the amount of sodium hydroxide required
= 88.4 mg of Mg x x x x...