Answer:
(C) Nathaniel can build at most 3 birdhouses.
Step-by-step explanation:
Given that:
[tex]43B+215H \leq 3000[/tex]
where:
Nathaniel wants to build 50 birds(B) using lego Blocks, we want to determine how many birdhouses(H) he can build with the remaining Lego blocks.
If B=50
[tex]43(50)+215H \leq 3000\\2150+215H \leq 3000\\\text{Subtract 2150 from both sides}\\215H \leq 3000-2150\\215H \leq 850\\\text{Divide both sides by 215}\\H \leq 3.95[/tex]
Therefore, Nathaniel can build at most 3 Birdhouses.