Respuesta :

Answer:

35meV

Explanation:

To find the average translational kinetic energy you use the followinf formula:

[tex]E_k=\frac{3}{2}k_BT[/tex]

K_B: Boltzman' constant = 1.38*10^-23 J/K

T: standard temperature = 273.15K

By replacing these values you obtain:

[tex]E_k=\frac{3}{2}(1.38*10^{-23}J/K)(273.15K)=5.65*10^{-21}J[/tex]

in eV you have:

5.65*10^-12(6.242*10^18eV)=0.035eV=35meV

Hence, the average translational energy is 35meV

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