Question

A two slit pattern is viewed on a screen 1.00m from the slits if the two third-order minima are 22.0 cm apart what is the width of the central bright fringe

Answer 1

Answer:

4.4 cm

Explanation:

Given:

Distance of the screen from the slit, D = 1 m

Distance between two third order interference minimas, x = 22 cm

Let's say, minima occurs at:

$x_n = (n + \frac{1}{2}) \frac{wL}{d}$

We have:

$2x_2 = 2(2 + \frac{1}{2}) * \frac{w*22}{d}$

Calculating further for the width of the central bright fringe, we have:

$\frac{w}{d} = \frac{22}{5}$

= 4.4 cm

Note: w in representswavelength

Answer 2

The width of the central bright fringe will be 4.4 cm. It is obtained by taking the minima.

What is the width of the central bright fringe?

The width of the central bright fringe is equally distant from another dark fringe on both sides of the central bright fringe.

The given data in the problem is;

D is the distance of the screen from the slit = 1 m

x  is the distance between two third-order interference minimal, = 22 cm

The minima occur at;

$\rm x_n = (n+\frac{1}{2} )\frac{wL}{d} \\\\ 2x_2 = 2(2+\frac{1}{2} )\frac{w\times 22}{d} \\\\ \frac{w}{d} =\frac{22}{5} \\\\ \frac{w}{d} =4.4 \ cm$

Hence the width of the central bright fringe will be 4.4 cm.

To learn more about the width of the central bright fringe refer;

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