The weights of soy patties sold by a diner are normally distributed. A random sample of 15 patties yields a mean weight of 3.8 ounces with a sample standard deviation of 0.5 ounces. At the 0.05 level of​ significance

Respuesta :

Complete Question

The weights of soy patties sold by a diner are normally distributed. A random sample of 15 patties yields a mean weight of 3.8 ounces with a sample standard deviation of 0.5 ounces. At the 0.05 level of significance,perform a hypothesis test to see if the true mean weight is  less than 4 ounce.

Answer:

Yes the true mean weight is less than 4 ounce

Explanation:

  From the question we are told that

     The random sample is [tex]n = 15[/tex]

       The mean weight is [tex]\= x = 3.8\ ounce[/tex]

        The standard deviation is  [tex]\sigma = 0.5 \ ounce[/tex]

         The  level of significance is  [tex]\alpha = 0.05[/tex]

       

So

   The  null hypothesis is  [tex]H_o : \mu \ge 4[/tex]

     The alternative hypothesis is [tex]H_a : \mu < 4[/tex]

Generally the critical value which a bench mark to ascertain whether the null hypothesis is  true or false is mathematically represented as

            [tex]t_{0.05} = 1.79[/tex]

This value is  obtained from  the critical value table

Generally the test statistics is mathematically represented as

                [tex]Test \ Statistics (ST) = \frac{\= x - \mu }{\frac{\sigma}{\sqrt{n} } }[/tex]

           =>  [tex]ST = \frac{3.8 -4 }{\frac{0.5}{\sqrt{20} } }[/tex]

                [tex]ST = - 1.79[/tex]

So since ST is less than [tex]t_{0.05}[/tex]  then the null hypothesis would be rejected and the alternative hypothesis would be accepted so

  Thus the true mean weight is less than 4

ACCESS MORE
EDU ACCESS
Universidad de Mexico