Question

A storekeeper wants to mix two types of flour to get 300 pounds, so he can sell it by 2.50$ per pound. If he uses flour worth $2.40 a pound with another flour worth $3.00 a pound, how many pounds of each does he use?

Answer 1

Answer:

• 250 pounds cheap flour
• 50 pounds expensive flour

Step-by-step explanation:

Let x represent the quantity of the more expensive flour. Then 300-x is the quantity of the less expensive flour. The total cost of the mix is ...

  3.00x +2.40(300-x) = 2.50(300)

  0.60x = 300(0.10) . . . . . simplify, subtract 2.40(300)

  x = 300/6 = 50 . . . . . . . . divide by 0.60. Quantity of expensive flour

  300-x = 250 . . . . quantity of cheaper flour

He should use 250 pounds of $2.40 flour, and 50 pounds of $3.00 flour.

Answer 2

The shopkeeper needs to mix 250 pounds of the first four with a price of $2.40, and 50 pounds of $3 flour.

What is an equation?

An equation is formed when two equal expressions are equated with the help of an equal sign "=".

Let the weight of the first flour be x pounds and the weight of the second flour be y pounds, therefore, the total weight of the mix can be written as

$x + y = 300\rm\ pounds$

We know that the average price of the mix is $2.50, while, the price of the first flour is $2.40, and the price of the second floor is $3. therefore, the equation can be written as,

$2.40x +3y = (300 \times 2.50)\\\\2.40x +3y = 750$

Now, as we know the two equations, solving the two equations we will get,

$x + y = 300\\y = 300 - x$

Substitute the value in the second equation,

$2.40x +3y = 750\\\\2.40x +3(300-x) = 750\\\\2.40x + 900 - 3x = 750\\\\0.60x = 150\\\\x = 250$

Substitute the value of x in the first equation,

$x + y = 300\\ 250 + y =300\\ y= 50$

hence, the shopkeeper needs to mix 250 pounds of the first four with a price of $2.40, and 50 pounds of $3 flour.

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