Question

Rectangle TUVW is on a coordinate plane at T(a,b) ,U(a+2,b+2),V(a+5,b-1) and W(a + 3, b - 3) )what is the slope of the line that is is parallel to the line that contains side WV?

Answer 1

Answer:

The slope parallel to the line that contains side WV is 1.

Step-by-step explanation:

1. The slope of parallel lines is also same.
2. The product of perpendicular lines is -1.

Slope formula:

The slope of a line by joining two points (x₁,y₁) and (x₂,y₂) is

$tan\theta=m= \frac{y_2-y_1}{x_2-x_1}$

Rectangle TUVW is on a coordinate plane at T(a,b), U(a+2,b+2),V(a+5,b-1) and W(a+3,b-3).

Here,x₁=a+3, y₁=b-3, x₂=a+5, y₂=b-1

Then the slope of line WV is

$=\frac{(b-1)-(b-3)}{(a+5)-(a+3)}$

$=\frac{b-1-b+3}{a+5-a-3}$

$=\frac{2}{2}$

=1

Since the slope of parallel sides is always equal.

Then the slope parallel to the line that contains side WV is 1.

Answer 2

The slope of the line that is is parallel to the line that contains side WV is 1.

Given: In Rectangle TUVW

T(a, b), ,U(a+2,b+2),V(a+5,b-1) and W(a + 3, b - 3)

To find the slope of the line that is is parallel to the line that contains side WV.

The slopes of parallel lines are equal.

Let:

$(x_{1} , y_{1} )= W(a+3,b-3)\\(x_{2} , y_{2} )= W(a+5,b-1)$

The slope of a line by joining two points (x₁,y₁) and (x₂,y₂) is

$m=\frac{y_{2} - y_{1} }{x_{2} - x_{1} }$

Then the slope of line WV is

$=\frac{(b-1)-(b-3)}{(a+5)-(a+3)} \\=\frac{b-1-b+3}{a+5-a-3} \\=\frac{2}{2} \\=1$

Therefore, The slope of the line that is is parallel to the line that contains side WV is 1.

For more information:

https://brainly.com/question/12203383