Question

Find fq, the vertical force that pier q exerts on the right end of the bridge. express the vertical force at q in terms of m and g

Answer 1

Answer:

$F_Q=\frac{Mg}{3}$

Explanation:

We are given that

Length of beam=L

Mass of object=M

We have to find the FQ , the  vertical force that pier exerts on the right end of the bridge .

Torque about P

$F_Q(3L)-MgL=0$

$F_Q(3L)=MgL$

$F_Q=\frac{MgL}{3L}$

$F_Q=\frac{Mg}{3}$

Hence, the force that exerted pier Q exerts on the right end  of the bridge is given by

$F_Q=\frac{Mg}{3}$