Answer:
474.59 mg/L
Explanation:
Given that
BOD = 30 mg/L
Original BOD = 30 mg/L × dilution factor
Original BOD = 30 mg/L × 10 = 300 mg/L
[tex]L_o = \frac{BOD}{1-e^{-5t}}[/tex]
here [tex]L_o[/tex] is the ultimate BOD ; BOD is the biochemical oxygen demand ; t = 0.20 /day
[tex]L_o = \frac{300}{1-e^{-5(0.20)}}[/tex]
[tex]L_o = 474.59 \ mg/L[/tex]