Question

5. Find the molality if 2.3 moles of glucose is dissolved in 500.0 g of water.

Answer 1

Answer:

The molality is 4.6 $\frac{moles}{kg}$

Explanation:

Molality (m) is a concentration measurement that indicates the number of moles of solute that are dissolved in 1 kilogram of solvent.

The Molality of a solution is determined by the following expression:

$Molality=\frac{number of moles of solute}{kilograms of solvent}$

The molality is expressed in units ($\frac{moles}{kg}$).

In this case:

• number of moles of solute: 2.3 moles
• kilograms of solvent: being 1 kg=1000 g, 500 g=0.5 kg

Replacing:

$Molality=\frac{2.3 moles}{0.5 kg}$

Solving:

Molality=4.6 $\frac{moles}{kg}$

The molality is 4.6 $\frac{moles}{kg}$