The area of the outer part of the rug is [tex]16 -x^2[/tex]
Since The side length of the inner square is x inches and the width of the outer region is 4 in.
We know that
Area of a square: Side²
So, area of the rug is
Area of the rug = 4² =16 in²
So based on this we can say that The area of the outer part of the rug is [tex]16 -x^2[/tex]
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