3.00 L of Ch4 is known to contain 0.650 moles at a certain temperature and pressure if the volume of a chamber of CH4 increased from 7.00L to 8.20 L how many moles CH4 were added assume temperature and pressure stayed constant

Respuesta :

Answer: 0.111 moles of [tex]CH_4[/tex] were added

Explanation:

According to the Avogadro's law, the volume of gas is directly proportional to the number of moles of gas at same pressure and temperature. That means,

[tex]V\propto n[/tex]

or,

[tex]\frac{V_1}{V_2}=\frac{n_1}{n_2}[/tex]

where,

[tex]V_1[/tex] = initial volume of gas  = 7.00 L

[tex]V_2[/tex] = final volume of gas = 8.20 L

[tex]n_1[/tex] = initial moles of gas  = 0.650 mole

[tex]n_2[/tex] = final moles of gas  = ?

Now we put all the given values in this formula, we get

[tex]\frac{7.00}{8.20}=\frac{0.650}{n_2}[/tex]

[tex]n_2=0.761[/tex]

Thus moles added are (0.761-0.650) = 0.111 moles

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