Question

3.00 L of Ch4 is known to contain 0.650 moles at a certain temperature and pressure if the volume of a chamber of CH4 increased from 7.00L to 8.20 L how many moles CH4 were added assume temperature and pressure stayed constant

Answer 1

Answer: 0.111 moles of $CH_4$ were added

Explanation:

According to the Avogadro's law, the volume of gas is directly proportional to the number of moles of gas at same pressure and temperature. That means,

$V\propto n$

or,

$\frac{V_1}{V_2}=\frac{n_1}{n_2}$

where,

$V_1$ = initial volume of gas  = 7.00 L

$V_2$ = final volume of gas = 8.20 L

$n_1$ = initial moles of gas  = 0.650 mole

$n_2$ = final moles of gas  = ?

Now we put all the given values in this formula, we get

$\frac{7.00}{8.20}=\frac{0.650}{n_2}$

$n_2=0.761$

Thus moles added are (0.761-0.650) = 0.111 moles