Answer:
2 feet
Step-by-step explanation:
We are given that
[tex]b_1=21 feet[/tex]
[tex]b_2=5feet[/tex]
Area of trapezoid=26 square ft
We have to find the height of the cross section.
We know that
Area of trapezoid=[tex]\frac{1}{2}(b_1+b_2)h[/tex]
Using the formula
[tex]26=\frac{1}{2}(21+5)[/tex]
[tex]26=\frac{1}{2}(26)h[/tex]
[tex]h=\frac{26\times 2}{26}=2 feet[/tex]
Hence, the height of cross section =2 feet