Answer:
Explanation:
Case-A
Block weight [tex]W=150\ lb[/tex]
Friction Force [tex]f=30\ lb[/tex]
and friction force is
[tex]f=\mu _kN[/tex]
where N=normal reaction (Usually equals to weight)
[tex]\mu _k=\frac{30}{150}[/tex]
[tex]\mu _K=\frac{1}{5}=0.2[/tex]
Case-B
Block weight [tex]W=20\ N[/tex]
Friction Force [tex]f=5\ N[/tex]
[tex]\mu _k=\frac{f}{N}[/tex]
[tex]\mu _k=\frac{5}{20}=\frac{1}{4}[/tex]
[tex]\mu _k=0.25[/tex]
Case-C
Block weight [tex]W=1500\ lb[/tex]
Friction Force [tex]f=60\ lb[/tex]
[tex]\mu _k=\frac{f}{N}[/tex]
[tex]\mu _k=\frac{60}{1500}[/tex]
[tex]\mu _k=0.04[/tex]