Question

Miguel is a golfer, and he plays on the same course each week. The following table shows the probability distribution for his score on one particular hole, known as the Water Hole. Score 3 4 5 6 7 Probability 0.15 0.40 0.25 0.15 0.05 Let the random variable X represent Miguel’s score on the Water Hole. In golf, lower scores are better. (a) Suppose one of Miguel’s scores from the Water Hole is selected at random. What is the probability that Miguel’s score on the Water Hole is at most 5 ? Show your work.

Answer 1

Answer:

a. p(x<= 5) = .15 + .4 + .25 = .8

C. .4(4.2) = 1.68

5.4(1-.4) = 3.24

3.24 + 1.68 = 4.92 ,, 4.92 > 4.55 so short is better

Step-by-step explanation:

Answer 2

The probability that Miguel’s score on the Water Hole is at most 5 is 80%.

Given that,

Miguel is a golfer, and he plays on the same course each week.

The following table shows the probability distribution for his score on one particular hole, known as the Water Hole.

Score 3 4 5 6 7

Probability 0.15 0.40 0.25 0.15 0.05.

We have to determine,

The probability that Miguel’s score on the Water Hole is at most 5.

According to the question,

Let the random variable X represent Miguel’s score on the Water Hole. In golf, lower scores are better.

Suppose one of Miguel’s scores from the Water Hole is selected at random.

Then,

The probability that Miguel’s score on the Water Hole is at most 5 is,

At most 5 means scores which are equal or less than 5.

P(at most 5) = P(X ≤ 5) = P(X = 3) + P(X = 4) + P(X = 5)

P(X ≤ 5) = 0.15 + 0.40 + 0.25

P(X ≤ 5) = 0.80

P(X ≤ 5) = 80%

Therefore,

There is 80% chance that Miguel’s score on the Water Hole is at most 5.

Hence, The probability that Miguel’s score on the Water Hole is at most 5 is 80%.

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