Question

Calculate the braking distance for a vehicle traveling at 30 mi/h (13.4 m/s) with an acceleration of - 9.0 (m/s)/s while breaking.

Answer 1

Answer:

Braking distance of vehicle is 9.97 m

Explanation:

It is given initial velocity of the vehicle u = 13.4 m/sec

Acceleration of the vehicle $a=-9m/sec^2$

As the vehicle finally stops so final velocity of the vehicle v = 0 m/sec

We have to find the braking distance s

From third equation of motion

$v^2=u^2+2as$

$0^2=13.4^2+2\times -9\times s$

s = 9.97 m

So braking distance of the vehicle is 9.97 m