If part of an electric circuit dissipates energy at 6 W when it draws a current of 3 A, what voltage is impressed across it?

P=6w
I=3A
V = ?

Respuesta :

Answer:2 volts

Explanation:

Power=current x voltage

6=3 x voltage

Divide both sides by 3

6/3=(3 x voltage)/3

2=voltage

Voltage=2volts

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