Answer:
19.2J
Explanation:
For a string-mass system the elastic potential energy is given by:
[tex]U=\frac{1}{2}kx^2[/tex]
k: spring's constant = 240N/m
x: compression = 0.40m
by replacing the values of k and x you obtain:
[tex]U=\frac{1}{2}(240N/m)(0.40m)^2=19.2J[/tex]
hence, the elastic potential energy is 19.2J
Answer:
19.2j I took the assessment and got it right :)
Explanation: