Question

Choose an expression for the acid ionization constant (Ka)(Ka) for HFHF. Choose an expression for the acid ionization constant for . Ka=[H3O+][F−][HF]Ka=[H3O+][F−][HF] Ka=[F−][H3O+][HF]Ka=[F−][H3O+][HF] Ka=[HF][H3O+][F−]Ka=[HF][H3O+][F−] Ka=[H3O+][HF][F−]Ka=[H3O+][HF][F−]

Answer 1

Answer:

$Ka = \frac{[F^{-}][H_3O^{+}]}{[HF]}$

Explanation:

Let's consider the acid dissociation of hydrofluoric acid according to Brönsted-Lowry theory.

HF(aq) + H₂O(l) ⇄ F⁻(aq) + H₃O⁺(aq)

The equilibrium constant for this reaction is known as acid ionization constant (Ka). It only includes aqueous species and gases if there were. The acid ionization constant is:

$Ka = \frac{[F^{-}][H_3O^{+}]}{[HF]}$