Answer:
The resultant elongation in the steel is 0.216 mm
The resultant elongation in the brass is 0.3927 mm
Explanation:
Given data:
L=240 mm
σ=180 MPa
Esteel=200 GPa=200x10³MPa
Ebrass=110 GPa=110x10³MPa
The mathematical expression for the elongation in the steel is:
[tex]Elongation_{steel} =\frac{\sigma *L}{E_{steel} } =\frac{180*240}{200x10^{3} } =0.216mm[/tex]
The mathematical expression for the elongation in the brass is:
[tex]Elongation_{brass} =\frac{\sigma *L}{E_{brass} } =\frac{180*240}{110x10^{3} } =0.3927mm[/tex]