Answer:
[tex]SO_{3}^{2-}(aq.)+2OH^{-}(aq.)\rightarrow SO_{4}^{2-}(aq.)+H_{2}O(l)+2e^{-}[/tex]
Explanation:
The given reaction is an example of oxidation reaction. The step-by-step balancing procedure has been shown below:
Chemical equation: [tex]SO_{3}^{2-}(aq.)\rightarrow SO_{4}^{2-}(aq.)[/tex]
Balance H and O in basic medium: [tex]SO_{3}^{2-}(aq.)+2OH^{-}(aq.)\rightarrow SO_{4}^{2-}(aq.)+H_{2}O(l)[/tex]
Balance charge: [tex]SO_{3}^{2-}(aq.)+2OH^{-}(aq.)\rightarrow SO_{4}^{2-}(aq.)+H_{2}O(l)+2e^{-}[/tex]
Balanced chemical equation:
[tex]SO_{3}^{2-}(aq.)+2OH^{-}(aq.)\rightarrow SO_{4}^{2-}(aq.)+H_{2}O(l)+2e^{-}[/tex]