Question

During the final 5 seconds of a race a cyclist increased her velocity from 4 m/s to 7 m/s . What was her average acceleration during those last 5 seconds

Answer 1

Answer:

The average acceleration of the cyclist was 0.6 m/s².

Step-by-step explanation:

Acceleration:

The rate change of velocity per unit time is call the acceleration of the object.

$a=\frac{v-u}t$

u= initial velocity

v= final velocity

t= time taken change of velocity.

During the final 5 seconds of a race cyclist increased her velocity from 4m/s to 7 m/s

Here v= 7 m/s and u=4 m/s t=5 seconds

$\therefore a=\frac{7\ m/s-4 \ m/s}{5s}$

     $=\frac{3}{5} \ m/s^2$

     =0.6 m/s²

The average acceleration of the cyclist was 0.6 m/s².

Answer 2

The average acceleration of the cyclist was 0.6 m/s².

Given that ,

• During the final 5 seconds of a race a cyclist increased her velocity from 4 m/s to 7 m/s .

• The calculation is as follows;

$= (7 - 4) \div 5\\\\= 3 \div 5$

= 0.6 m/s^2

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