Answer: The volume occupied by the gas is 5295.1 L
Explanation:
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
Given mass of hydrogen gas = 454.5 g
Molar mass of hydrogen gas = 2 g/mol
Putting values in above equation, we get:
[tex]\text{Moles of hydrogen gas}=\frac{454.5g}{2g/mol}=227.25mol[/tex]
To calculate the volume, we use the equation given by ideal gas equation:
PV=nRT
where,
P = pressure of the gas = 1.050 at
m
V = Volume of gas = ?
n = number of moles of gas = 227.25 moles
R = Gas constant = [tex]0.0821\text{ L atm }mol^{-1}K^{-1}[/tex]
T = temperature of the gas = [tex]25^oC=[25+273]K=298K[/tex
]
Putting values in above equation, we get:
[tex]1.050atm\times V=227.25mol\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 298K\\\\V=\frac{227.25\times 0.0821\times 298}{1.050}=5295.1L[/tex]
Hence, the volume occupied by the gas is 5295.1 L
