Question

Explain the term duty cycle and determine the pulse duration of a periodic pulse train whose duty cycle is 15% and frequency is 13.3Mhz. Interprete your results.

Answer 1

Answer:

Duty cycle of a signal measures the fraction of a  time of a given transmitter is transmitting that signal. This fraction of a time determines the overall or total power transmitted or delivered by that signal.

• More power is possessed by duty cycles with longer signals. This gives the signal the following characteristics such as reliability, strength and easy detection and thus require less efficient receivers.
• Less power is associated  with duty cycles of shorter signals. This gives the signal the following characteristics  such as less reliability, lower strength and not easily detected and thus require more efficient receivers.

Duty cycle = 15 %

frequency =  13.3Mhz = 13.3 x 10^3 hz = I/T = F

T = period = 1 / F = 1/13.3 x 10^3 hz= 7.5188 x 10 ^-5 s

Duty cycle = pulse duration/ period

15 % = PD/7.5188 x 10 ^-5 s

PD = 15/100 X 7.5188 x 10 ^-5 s = 1.12782 x 10^ -5 s

INTERPRETATION OF RESULTS

With a duty of 15 % and pulse duration of 1.12782 x 10^ -5 s, the strength is low , short signal and less reliable and needs more efficient receiver

Explanation:

Duty cycle of a signal measures the fraction of a  time of a given transmitter is transmitting that signal. This fraction of a time determines the overall or total power transmitted or delivered by that signal.

• More power is possessed by duty cycles with longer signals. This gives the signal the following characteristics such as reliability, strength and easy detection and thus require less efficient receivers.
• Less power is associated  with duty cycles of shorter signals. This gives the signal the following characteristics  such as less reliability, lower strength and not easily detected and thus require more efficient receivers.

Duty cycle = 15 %

frequency =  13.3Mhz = 13.3 x 10^3 hz = I/T = F

T = period = 1 / F = 1/13.3 x 10^3 hz= 7.5188 x 10 ^-5 s

Duty cycle = pulse duration/ period

15 % = PD/7.5188 x 10 ^-5 s

PD = 15/100 X 7.5188 x 10 ^-5 s = 1.12782 x 10^ -5 s

INTERPRETATION OF RESULTS

With a duty of 15 % and pulse duration of 1.12782 x 10^ -5 s, the strength is low , short signal and less reliable and needs more efficient receiver