Respuesta :
Answer:
Step-by-step explanation:
We would determine the area to the left of z = 0.49 on the normal curve and subtract it from the area to the left of z = 2.05 on the normal curve
Therefore,
For z = 0.49,
Probability value = 0.6879
For z = 2.05
Probability value = 0.9798
Therefore, the area under the standard normal curve to the left of z = 0.49 and to the right of z = 2.05 is
0.9798 - 0.6879 = 0.2919
The area will be "0.7081".
According to the question,
The area under standard normal curve to left of,
- [tex]z = 0.49[/tex]
To the right of,
- [tex]z = 2.05[/tex]
Now,
The Area will be:
= [tex]P[z< 0.49]+P[z>2.05][/tex]
= [tex]P[z< 0.49]+1-P[z< 2.05][/tex]
= [tex]0.6879+1-0.9798[/tex]
= [tex]0.7081[/tex]
Thus the above answer is right.
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