Answer:
At pH = 6.19, solution begin to show precipitation
Explanation:
Ksp of Al(OH)₃ is:
Al(OH)₃(s) ⇄ Al³⁺(aq) + 3 OH⁻(aq)
At equilibrium:
Ksp = 2x10⁻³² = [Al³⁺] [OH⁻]³
0.4M Al(OH)₃ produce:
[Al³⁺] = X
[OH⁻] = 3X
Replacing:
2x10⁻³² = [X] [3X]³
2x10⁻³² = 27X⁴
7.41x10⁻³³ = X⁴
5.217x10⁻⁹ = X
Thus:
[OH⁻] = 3X = 3×5.217x10⁻⁹
[OH⁻] = 1.565x10⁻⁸M
pOH = - log [OH⁻] = 7.805
pH = 14 - pOH
pH = 6.19
Thus, at pH = 6.19, solution begin to show precipitation.