I need help with this questions! I need to find AB and BC

Answer:
here is answer.
Step-by-step explanation:
by sin law..
put
BC= (AC/sin60)*sin30 ( i have skipped ione line)
=...
and by putting value of ac u will get BC.
THEN.
by pythagoras
AB=
[tex] \sqrt{ac {}^{2} + bc { }^{2} } [/tex]
put value u will get answer